Question

If banaras is coded as 238 and delhi is coded in 168 then patna is coded as

Answer 1

Step-by-step explanation:

Given  

If BANARAS IS CODED AS 238, Delhi is coded as 168 then PATNA IS CODED AS ?

Based on alphabets we get A = 1 etc,

B A N A R A S = 2 + 1 + 14 + 1 + 18 + 1 + 19 = 56

Now number of letters = 7

So Banaras is coded as 238

So 238 – 56 / 7 = 26

Now for D E L H I  = 4 + 5 + 12 + 8 + 9 = 38

So Delhi is coded as 168

Now number of letters is 5

So 168 – 38 / 5 = 26

We now know 26 is common.

So P A T N A = 16 + 1 + 20 + 14 + 1 = 52

So number of letters is 5

So x – 52 / 5 = 26

So x – 52 = 130

So x = 130 + 52

So x = 182

So Patna is coded as 182

Answer 2

In this sum, we will follow the alphabetical position of each word,

BANARAS = 2+1+14+1+18+1+19=56,

number given for BANARAS is 238

Total number of alphabets in BANARAS =7

so (238 - 56)÷ 7=182÷7= 26,

DELHI = 4+5+12+8+9= 38

total number of alphabets in DELHI =5

according the sum DELHI =168

therefore,(168-38)÷5 =130÷5=26

for both words "26 " is a coding number,

for PATNA = 16+1+20+14+1=52

total number of alphabet in PATNA = 5

let consider x is the number for PATNA,

(x-52)÷5 = 26

x-52 =26×5

x = 130+52 =182,

Ans:--PATNA is coded as 182,