Question

if bars =10and. Beert=10 then deez will be?

Answer 1

add the positive values of alphabet ...
B+A+R+S= 2+1+18+19 = 40

BARS =40/4=10

B+E+E+R+T =2+5+5+18+20 =50

BEERT = 50/5=10

D+E+E+Z= 4+5+5+26 =40

DEEZ =40/4=10 ..

Answer 2

Answer:

DEEZ = 10

Step-by-step explanation:

Hey Mate,

Hope you remember Conversion Table (A => 1, B => 2, C => 3, D => 4, E => 5, F => 6, G => 7, H => 8, I => 9, J => 10, K => 11, L => 12, M => 13, N => 14, O => 15, P => 16, Q => 17, R => 18, S => 19, T => 20, U => 21, V => 22, W => 23, X => 24, Y => 25, Z => 26.)

Take BARS.

BARS => 2 + 1 + 18 + 19 => 40

BARS => 40/ 4 => 10 .

Divide from the first digit of the number.

Take BEERT,

BEERT => 2 + 5 + 5 + 18 + 20 => 50  

BEERT => 50/ 5 => 10

Divide from the first digit of the number.

Now, Take DEEZ

DEEZ => 4 + 5 + 5 + 26 => 40  

DEEZ => 40/ 4 => 10

Divide from the first digit of the number.