Question

If base and perpendicular of right angled

triangle are 7cm and 8cm than hypotenuse

will be

a)15cmb) 113cm
c)√113 cm d)√13 cm​

Answer 1

Given :-

• Base of a right angled triangle = 7 cm.
• Perpendicular of right angled triangle = 8 cm.

To Find :- Hypotenuse will be

a)15cm

b) 113cm

c)√113 cm

d)√13 cm.

Answer :-

we know that, In right angled ∆ , by pythagoras theorem,

→ (Perpendicular)² + (Base)² = (Hypotenuse)²

so, putting given values we get,

→ (8)² + (7)² = (Hypotenuse)²

→ (Hypotenuse)² = 64 + 49

→ (Hypotenuse)² = 113

square root both sides now,

→ Hypotenuse = √113 cm (C) (Ans.)

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Answer 2

SOLUTION

TO CHOOSE THE CORRECT OPTION

If base and perpendicular of right angled triangle are 7cm and 8cm than hypotenuse will be

a) 15 cm

b) 113 cm

c) √113 cm

d) √13 cm

CONCEPT TO BE IMPLEMENTED

Pythagoras theorem :

In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the remaining two sides

EVALUATION

Here it is given that base and perpendicular of right angled triangle are 7 cm and 8 cm

Therefore

Base = B = 7 cm

Perpendicular = P = 8 cm

Hypotenuse = H = ?

Now according to Pythagoras Theorem

Hypotenuse² = Base² + Perpendicular²

$\sf{ \implies \:{ H }^{2} = {B}^{2} + { P }^{2} }$

$\sf{ \implies \:{ H }^{2} = {(7)}^{2} + {(8)}^{2} }$

$\sf{ \implies \:{ H }^{2} = 49 + 64 }$

$\sf{ \implies \:{ H }^{2} = 113 }$

$\sf{ \implies \: H = \sqrt{113} }$

Hence Hypotenuse = √113 cm

FINAL ANSWER

Hence the correct option is c) √113 cm

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