If base current is 50 a .Find the range of collector current
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For an unbiased transistor, considering only the BE junction which is a pn junction diode, 0.7V is the potential barrier. In an npn transistor base is positive(p) and emitter is negative(n). So the potential barrier vbe=0.7V.
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Explanation:
Ib=50 micro amp
B = 25
Ic = Current gain
Ic= Ib × β
== 50×25
==1250 ma
==1250/1000 =1.25 ma
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