Question

if base f a
parallelegram is 18cm and it's
height is licom find is area​

Answer 1

$\huge \fbox \red{solution}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \huge \bf\underline \red{{let}}$

$\bf{BCD \: is \: a \: || \: where }$

$\bf{Base = AD = BC = 18 \: Cm}$

$\bf{Height = AM = CN = 11 \: Cm}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf \underline \pink{Now,}$

$\bf{Area \: of \: the \: ∆ \: ABC = \frac{1}{2} \times AM × BC}$

$= \bf{( \frac{1}{2} \times 11 \times 18)sq.cm}$

$= \bf{99cm}$

$\bf \: Area \: of \: the \: ||$

$\bf = 2 × Area \: of \: ∆ \: ABC$

$\bf = (2 \times 99)sq.cm$

$\bf = 198 \: sq.cm$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf \huge \underline \red{or}$

$\bf{We \: know \: that}$

$\bf{Area \: of \: a \: || = B × H}$

$\bf \underline \red{Here}$

$\bf \: Base \: of \: t he \: || , AD = BC = 18cm$

$\bf \: Height \: of \: the \: || ,AM = CN = 11 Cm$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf \: Area \: of \: the \: ||$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf \: = B × H$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf \: AD = AM$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf \: = (18 \times 11) \: sq.cm$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf = 198 \: sq.cm$

Answer 2

Answer:

198 sq.cm

Explanation:

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