If base of an isoceles triangle measures 24cm and its area is 60cmsq find its perimetre
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i hope this will help you
area of isosceles triangle is heigth*base/2
60=hieght*24/2
60=hieght*12
60/12=hieght
5=hieght
by pythgoras theorem,
side^2=5^2 + 12^2
side^2=25+144
side^2=169
side=13
perimeter =13+13+24
perimeter=50cm
area of isosceles triangle is heigth*base/2
60=hieght*24/2
60=hieght*12
60/12=hieght
5=hieght
by pythgoras theorem,
side^2=5^2 + 12^2
side^2=25+144
side^2=169
side=13
perimeter =13+13+24
perimeter=50cm
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