if base of an isosceles triangle is 12 cm and its perimeter is 38 cm find the area of the triangle
Answers
Answer:
69.2 cm^2
Step-by-step explanation:
Let the equal side be x cm.
Perimeter of the triangle = 38
=> 2x + 12 = 38
=> 2x = 26
=> x = 13 cm
We find S,
S = (a + b + c)/2
= (13 + 13 + 12)/2
= 19 cm
By using heron's formula.
A = √s(s - a)(s - b)(s - c)
= √19(19 - 13)(19 - 13)(19 - 12)
= √19 * 6 * 6 * 7
= √4788
= 69.2 cm^2
Hence, Area of triangle = 69.2 cm^2
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Step-by-step explanation:
The base of the isosceles triangle is
b =12 cm and let L be two
legs of the isosceles triangle. Perimeter of the isosceles triangle
is
P =b+2l
38=12+2l
2l =38-12
2l=26
l=13 cm . cm. Legs of the isosceles triangle are
13
cm each.
Area of the isosceles triangle is
is
A=b/4 . √4 .l²-b²
A =12/4.√4.13²-12²
A=3.√532
≈69.2(1dp)
sq.cm
Area of the isosceles triangle is
69.2
sq.cm. [Ans]
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