Math, asked by sony1010, 1 year ago

if base of an isosceles triangle is 12 cm and its perimeter is 38 cm find the area of the triangle​

Answers

Answered by Anonymous
2

Answer:

69.2 cm^2

Step-by-step explanation:

Let the equal side be x cm.

Perimeter of the triangle = 38

=> 2x + 12 = 38

=> 2x = 26

=> x = 13 cm

We find S,

S = (a + b + c)/2

  = (13 + 13 + 12)/2

  = 19 cm

By using heron's formula.

A = √s(s - a)(s - b)(s - c)

   = √19(19 - 13)(19 - 13)(19 - 12)

   = √19 * 6 * 6 * 7

  = √4788

  = 69.2 cm^2

Hence, Area of triangle = 69.2 cm^2

#MarkAsBrainliest

Answered by Raunak1432
0

Step-by-step explanation:

The base of the isosceles triangle is

b =12 cm and let L be two

legs of the isosceles triangle. Perimeter of the isosceles triangle

is

P =b+2l

38=12+2l

2l =38-12

2l=26

l=13 cm . cm. Legs of the isosceles triangle are

13

cm each.

Area of the isosceles triangle is

is

A=b/4 . √4 .l²-b²

A =12/4.√4.13²-12²

A=3.√532

≈69.2(1dp)

sq.cm

Area of the isosceles triangle is

69.2

sq.cm. [Ans]

mark as a brainlist

Similar questions