if base of an isosceles triangle is 12cm and its perimeter is 35 cm find the area of the triangle.
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A=bhb
2
P=2a+b
hb=a2﹣b2
4
Solving forA
A=1
4bP(P﹣2b)=1
4·12·35·(35﹣2·12)≈58.86425cm²
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