Question

if base radius of a right circular cylinder is halved,keeping the height same,find the ratio of the volume of the reduced cylinder to that of the original cylinder.

Answer 1

volume of orignal cylinder=pie *r square*h. volume of new cylinder= pie*r/2 square*h. therefore. ratioes of volumes of two cylinders=pie*r square*h/pie rsquare/2*h. that is 1/1/4=4/1.

Answer 2

Answer:

$\huge\mathcal\pink{Solution:-}$

☘ Answer:-

1 : 4

☘ Step-by-step explanation:-

Let r be the radius of the base and h be the height of the given cylinder.

As per the condition given, radius of the base and the height of the reduced cylinder are r/2 and h respectively.

Now,

Let V1 and V2 be the volumes of the given cylinder and reduced cylinder respectively.

Then,

V1 = πr²h cubic units and,

V2 = π [r/2]²h = π/4 r²h cubic units.

=> V1/V2 = πr²h/π (r²/4)h = 4 => V2/V1 = 1/4

☞ V2 : V1 = 1:4