if base radius of a right circular cylinder is halved keeping the height same find the ratio of the volume of the reduced cylinder to that of the original cylinder
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let the radius be 2r and height be h
volume,1 = πr square h
= π4r square h
now , radius = r and height = h
volume,2 = πr square h
ratio = volume 2/ volume 1
= πr square h/ π4r square h
=1/4 = 1:4
volume,1 = πr square h
= π4r square h
now , radius = r and height = h
volume,2 = πr square h
ratio = volume 2/ volume 1
= πr square h/ π4r square h
=1/4 = 1:4
abhijeet8812:
thanks you my problem is solved
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