Question

if base radius of right circular cylinder is halved , keeping the height then find the ratio of the volume of the reduced
cylinder to that of the original cylinder

Answer 1

Beacuse all other values including π and h are constant and new radius is r/2
Volume of new solid=1/4of the old solid

Answer 2

Hola Friend ✋✋✋

Let the radius be 'r'
And height be 'h'

Volume of original cylinder = πr²h

When 'r' is halved ,new radius is
$\frac{r}{2}$


So new volume is ....
$= \pi( { \frac{r}{2} )}^{2} h \\ \\ = \frac{\pi {r}^{2}h }{4}$


So ratio of volume of the reduced cylinder to taht of orginal cylinder is ....

$\frac{\pi {r}^{2}h }{ \frac{\pi {r}^{2} h}{4} } \\ \\ = \frac{4}{1} \\ \\ so \: ratio \: is \: 4: 1$


Hope it helps