Question

If bbt + tbe = belt, then what will be the value of b + e + l + t?

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

bbt+tbe=belt

As

$(t+e)=t\\\\\therefore e=t-t=0$

$b+t=b\times10$

And $b<10$ and $t<10$

$(b+t)<20$

therefore value of $(b+t)=10$

Therefore

$(b+t)=b\times10\\\\(1+t)=1\times10\\\\t=9$

As

$(b+b)=l\\\\\therefore l=(1+1)=2$

Therefore

$(b+e+l+t)=(1+0+2+9)=12$