If bc + ca + ab = 0.Then,
bc/a^2 + ca/b^2 + ab/c^2 =?
A) - 2 B) 2 C) 3 D) - 3
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Solution :
It is given that ,
bc + ca + ab = 0 -----( 1 )
*******************************
We know that ,
If x + y + z = 0 then
x³ + y³ + z³ = 3xyz
********************************
Now ,
bc/a² + ca/b² + ab/c²
= [ ( bc )³ + (ca)³ + ( ab )³ /( abc )² ]
= [ 3(bc)(ca)(ab) ]/( abc )²
[ from using identity ]
= [3 ( abc )² ]/( abc )²
= 3
Option ( C ) is correct.
••••••
It is given that ,
bc + ca + ab = 0 -----( 1 )
*******************************
We know that ,
If x + y + z = 0 then
x³ + y³ + z³ = 3xyz
********************************
Now ,
bc/a² + ca/b² + ab/c²
= [ ( bc )³ + (ca)³ + ( ab )³ /( abc )² ]
= [ 3(bc)(ca)(ab) ]/( abc )²
[ from using identity ]
= [3 ( abc )² ]/( abc )²
= 3
Option ( C ) is correct.
••••••
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