History, asked by mathschamp23, 10 months ago

If bc+ca-ab = 125 & a^2 +b^2 +c^2 = 314, then value of a+b-c is? ​

Answers

Answered by Anonymous
19

Answer:

a+b-c = √64 = 8.

✔️Hope it will help you.✔️

Attachments:
Answered by streetburner
2

Answer:

8

Explanation:

bc+ca-ab = -(-bc-ca+ab) = 125

{a+b+(-c)}^2 =a^2 +b^2 +c^2 +2(ab-bc-ca)

= 314+2(-125)

= 64

a+b-c = √64 = 8

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