Question

if BC is a diameter of a circle of centre O and OD is perpendicular to the chord AB of the circle, show that CA = 2(OD)

Answer 1

OD is perpendicular to AB and hence also happens to bisect it. Similarly BC is bisected at O. So triangles ABC and DBO are similar with ratio of sides = 2. Hence CA = 2(OD)

Answer 2

Answer:

OD is perpendicular to AB and hence also happen to bisects similarly BC is bisected at O.So triangles ABC and DBO are similar with ratio of sides=2.Hence, CA=2(OD)