If BCA then n(AnB) is
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Let the C.P. of the 1^st scooter = Rs. x . Then, C.P. of the 2^nd scooter = Rs. (18000 - x) S.P. of 1^st scooter = Rs. x × 125100 = Rs. 5x4 S.P. ...
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the answer is n(A-B)
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