Question

If BD is perpendicular to AC and CE is perpendicular to AB ,prove that (1)∆AEC~ ∆ADB (2) CA/AB=CE/DE

Answer 1

Answer:

In △ ADB and △ AEC∠A = ∠A [Common]∠ADB = ∠AEC [Each 90°]∴ △ADB ~ △ AEC [AA − Similarity]then, ADAE = ABAC [Corresponding sides of 2 similartriangles are proportional]⇒ AB × AE = AC × AD HENCE PROVED

Was this answer helpful26