Math, asked by emmanuelcolina4649, 3 months ago

If BE=5, CE=10, and DE=13, find AE.

Answers

Answered by Anonymous
15

\huge\red{\mid{\underline{\overline{\textbf{Solution⤵}}}\mid}}

BE = 5, CE = 10, DE = 13, AE = ...

⚫ Here's how I did it.

➡ Assuming the value of "E" to be constant and allowing the initial letters to decrease by 2 each, we have

➪ A E = - 2

➵ 5 - 7 = - 2

➪ B E = 5

➵ 10 - 5 = 5

➪ C E = 10

➵ 13 - 3 = 10

➪ D E = 13

(OR)

If it's in sequence, the following is also possible.

✒ B E = 2 + 5 - 2 = 5

✒ C E = 3 + 5 + 2 = 10

✒ D E = 4 + 5 + 4 = 13

✒ A E = 1 + 5 - 4 = 2

Dear Mate!

I'm afraid I'm not so confident of my answer. Please cross-check it with the person who'll be answering it next.

If I had that wrong, I sincerely apologize.

Answered by Anonymous
3

 \huge \underline \bold \green{Answer}

➡ Assuming the value of "E" to be constant and allowing the initial letters to decrease by 2 each, we have

➪ A E = - 2

➵ 5 - 7 = - 2

➪ B E = 5

➵ 10 - 5 = 5

➪ C E = 10

➵ 13 - 3 = 10

➪ D E = 13

(OR)

If it's in sequence, the following is also possible.

✒ B E = 2 + 5 - 2 = 5

✒ C E = 3 + 5 + 2 = 10

✒ D E = 4 + 5 + 4 = 13

✒ A E = 1 + 5 - 4 = 2

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