If α , β be the zeroes of the quadratic polynomial 2 – 3x – x
2
then find the
value of α + β (1 + α )
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3
α + β = 3/ (-1)
α β = 2/(-1)
(x -α ) (x- β) = x*2 - (α + β) x + α β =0
Given equation is written as
x^2 + 3x -2 = 0
Comparing the equations
α β = -2
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