Question

if be3+ and a proton are accelerated by the same potential, their de - broglie wavelengths have the ratio? (assume mass of proton= mass of neutron) (Be= 9)

Answer 1

Answer:

Explanation:

As be is in +3 hence the the value of eV or electron volt will be 3eV.

Now, to use the formulae to find wavelength = h/✓(2meV) .

Where, let mass of proton be mp then mass of berelium will be 9mp.

Now, putting the values of m, and eV in the equation we get h/✓(2*9m*3eV).

Thus, the ratio of wavelengths of boron to that of the neutron will be 1/3✓3 . This we can find by dividing the wavelength of normal neutron to that of wavelength of berelium.

Answer 2

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hence the the value of eV or electron volt will be 3eV. Now, to use the formulae to find wavelength = h/ V(2meV). Where, let mass of proton be mp then mass of berelium will be 9mp. Now, putting the values of m, and eV in the equation we get h//(2*9m*3eV). Thus, the ratio of wavelengths of boron to that of the neutron will be 1/3/3. This we can find by dividing the wavelength of normal neutron to that of wavelength of berelium.