if body covers X1 distance with speed V1 and X2 distance with speed V 2 then v average =??
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Now T1 = X1/V1
and T2 = X2/V2
Then average velocity (V) = (X2–X1) / (T2–T1) ....(i)
putting the value of T1 and T2 in eq... (i) we get
V=(V1.V2.X2–X1.V1.V2) / (X2.V1–X1.V2)
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