if body starting from rest and moving with constant acceleration covers 20m in the 3rd second distance travel in second will be
Answers
Answered by
0
Answer:
24.5 m
Explanation:
u = 0 m/s & s = 20 m & t = 3 s
s = ut + 1/2 at²
s = 0 + 1 /2 at²
after 1 second
s1 = 1/2 x 9.8 x 1² = 4.9 m
after 2 seconds
s2 = 1/2 x 9.8 x 2² = 19.6 m
after 3 seconds
s3 = 1/2 x 9.8 x 3² = 44.1 m
so distance covered after 3 second is
s3 - s2 = 44.1 - 19.6 = 24.5 m
Similar questions