Question

If body starts from rest & aquires velocity of 12m/s in 5second. Calculate the acceleration & distance moved by body.

Answer 1

Answer:

acceleration is 2.4 m/sec square and distance is 60 m

Answer 2

Answer:

If the body starts from rest & acquires a velocity of 12m/s in 5second, the acceleration & the distance moved by the body are $2.4m/s^{2}$ and 30m respectively

Explanation:

• We know the equations of motions

       $V=u+at$ and $S=ut+\frac{1}{2}at^{2}$

where,

V- the final velocity

u- the initial velocity

a- acceleration of the body

t- time to change the velocity

S- distance moved

using the first equation of motion acceleration of the body is

$a=\frac{V-u}{t}$

from the question, we have

the final velocity $V= 12m/s$

the body starts from rest so the initial velocity $u=0$

the time taken $t=5s$

therefore the acceleration $a=12/5=2.4m/s^{2}$

put the values in the second equation we get

the distance traveled $S=0+\frac{1}{2} *2.4*5^{2} =30m$