Question

If both 112 and 33 are factors of the number a 43 62 1311, what is the smallest possible value of a'?

Answer 1

Answer:

Step-by-step explanation:

112 = 16 * 7  

33 = 11 * 3  

a * 43 * 62 * 1311 = (2 ^4 * 7) * k1  

a * 43 * 31 * 2 * 1311 = (2^4 *7) * k1  

a * 43 * 31 * 2 * 3 *437 = (2^4 *7) * k1  

therefore minimum value of a shud be 2^3 * 7 = 56  

for the second factor,  

a * 43 * 62 * 1311 = (11 * 3) * k2  

a * 43 * 31 * 2 * 3 *437 = (11 * 3) * k2  

so min = 11  

on the whole it shud be 56 * 11 = 616