If both 112 and 33 are factors of the number a 43 62 1311, what is the smallest possible value of a'?
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Answer:
Step-by-step explanation:
112 = 16 * 7
33 = 11 * 3
a * 43 * 62 * 1311 = (2 ^4 * 7) * k1
a * 43 * 31 * 2 * 1311 = (2^4 *7) * k1
a * 43 * 31 * 2 * 3 *437 = (2^4 *7) * k1
therefore minimum value of a shud be 2^3 * 7 = 56
for the second factor,
a * 43 * 62 * 1311 = (11 * 3) * k2
a * 43 * 31 * 2 * 3 *437 = (11 * 3) * k2
so min = 11
on the whole it shud be 56 * 11 = 616
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