Question

if both a and b are real numbers, then find the value of a and b in the following equality :-
√2+√3 / 3√2-2√3. =a-b√6
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Answer 1

Answer:

a = 2, b = (-5√6) / 6

Step-by-step explanation:

$\frac{\sqrt[]{2} + \sqrt[]{3} }{3\sqrt[]{2} - 2\sqrt[]{3} } = a - b\sqrt[]{6}$

⇒(√2 + √3) * (3√2 + 2√3) / (3√2 - 2√3) * (3√2 + 2√3) = a - b√6

⇒√2(3√2 + 2√3) + √3(3√2 + 2√3) / (3√2)² - (2√3)² = a - b√6

⇒(6 + 2√6 + 3√6 + 6) / (18 - 12) = a - b√6

⇒(12 + 5√6) / 6 = a - b√6

⇒12 / 6 + 5√6 / 6 = a - b√6

⇒12 / 6 - (-5√6) / 6 = a - b√6

⇒a = 12 / 6 = 2

⇒b = -5√6 / 6

# HOPE IT WILL HELP YOU

Answer 2

Answer:

b=-5√6/6

Step-by-step explanation:

Correct answer...............