Question

If both ax^3+2x^2-3 and x^2-ax+4 leave the same remainder,when divided by (x-2),then the value of 'a' is​

Answer 1

Step-by-step explanation:

ax^3+2x^2-3 and x^2 - ax + 4. when divided by (x-2) [here x=2] a(2)^3+2(2)^2-3. 8a + 8-3. 8a= -5. therefore a= -5/8