If both inputs of an s-r flip-flop are low, what will happen when the clock goes high?
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there will be no changes in the output
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if both inputs of s and r are low and clock is high then it will act as memory means whatever be the previous state that only it store.
CLK S R QN+1
0 x x QN(memory)
1 0 0 QN(memory)
1 0 1 0
1 1 0 1
1 1 1 invalid
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