if both numerator and denominator of the following fraction 2/5 are divided by 2, then the fraction
(a) becomes greater
(b) because lesser
(c) become 1
please solve and answer.
Answers
Answer:
option B) -46.32 kJ/mol
Explanation:
Given :
For a cell reaction \rm 2Fe^{+3}+2I^{-} \longrightarrow 2Fe^{+2}+I_22Fe
+3
+2I
−
⟶2Fe
+2
+I
2
, E = 0.24 V at 298 K
To find :
the standard Gibbs energy of the cell reaction
Solution :
The standard Gibbs energy of a cell reaction is given by,
\longmapsto \boxed{\sf \triangle G^{\circ}=-nFE^{\circ} _{cell}}⟼
△G
∘
=−nFE
cell
∘
where
n is the number of electrons transferred
Given cell reaction,
\rm 2Fe^{+3}+2I^{-} \longrightarrow 2Fe^{+2}+I_22Fe
+3
+2I
−
⟶2Fe
+2
+I
2
Oxidation half reaction :
\rm 2I^{-} \longrightarrow I_2+2e^{-}2I
−
⟶I
2
+2e
−
Reduction half reaction :
\rm 2Fe^{+3} +2e^{-} \longrightarrow 2Fe^{+2}2Fe
+3
+2e
−
⟶2Fe
+2
⇒ The number of electrons transferred = 2
So,
\begin{gathered}\rm \triangle G^{\circ}=-nFE^{\circ} _{cell} \\\\ \rm \triangle G^{\circ}=-2 \times 96500 \times 0.24 \\\\ \rm \triangle G^{\circ}=-46320 \ J/mol \\\\ \underline{ \rm \triangle G^{\circ}=-46.32 \ kJ/mol}\end{gathered}
△G
∘
=−nFE
cell
∘
△G
∘
=−2×96500×0.24
△G
∘
=−46320 J/mol
△G
∘
=−46.32 kJ/mol
Answer:
if both numerator and denominator of the following fraction 2/5 are divided by 2, then the fraction
(a) becomes greater
(b) because lesser
(c) become 1
please solve and answer.
Step-by-step explanation: