If both roots of x^2 -2011x+k =0 be prime numbers then find the number of possible values of k
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But in fact there are as many of these systerns as there are prime numbers, that is to say, there is an inf. dite number of these ... which serves to given times the transcendent can be divided into two of a simpler nature, and this substitution gives sin ... all the values 0, 1, 2 . . if we put instead of sin am : any other root, sin am § - 4a K - Auoi K' n , it will thus be symmetrical ... K = 4 m'i K' na Now giving a, 8 all possible values produces no combinations, and thereby the values of all the roots.
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