Question

If both the charges and distance between them is doubled then new electrostatic force

Answer 1

Answer:

please see the attachment

Answer 2

FORCE REMAINS UNCHANGED.

Given:

• Charges & distance both are doubled.

To find:

• New electrostatic force ?

Calculation:

Let initial charges be Q and q and the distance of separation of d.

So, initial electrostatic force is:

$F = \dfrac{kQq}{ {d}^{2} }$

• 'k' is COULOMB'S CONSTANT.

Now, the charges are 2q and 2Q. The distance becomes 2d.

So, new force is :

$F_{2} = \dfrac{k(2Q)(2q)}{ {(2d)}^{2} }$

$\implies F_{2} = \dfrac{4kQq}{ 4{d}^{2} }$

$\implies F_{2} = \dfrac{kQq}{ {d}^{2} }$

$\implies F_{2} = F$

So, the force remains unchanged.