Question

If both the length and breadth of a battery is 8cm. Then what should be the maximum width of the battery so that 2 identical batteries can be fit in a cubical case having surface area 600 sq. cm. ?

Answer 1

Answer:

Width = 100 cm

Step-by-step explanation:

l = 8cm

b = 8cm

w = ?

Surface Area of battery =2lw+2lh+2hw

2(LB+BH+HL) = 600

2(64 + 8H +8H) = 600

64 + 16H = 300

16H = 236

H = 236/16

H = 14.75cm