If both the length and breadth of a battery is 8cm. Then what should be the maximum width of the battery so that 2 identical batteries can be fit in a cubical case having surface area 600 sq. cm. ?
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Answer:
Width = 100 cm
Step-by-step explanation:
l = 8cm
b = 8cm
w = ?
Surface Area of battery =2lw+2lh+2hw
2(LB+BH+HL) = 600
2(64 + 8H +8H) = 600
64 + 16H = 300
16H = 236
H = 236/16
H = 14.75cm
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