if both the supply pipe and waste pipe are opened together, then an empty tank can be filled in 12 hours. but if only thd supply pipe is opened, then an empty tank can be filled in 4 hours. in how many hours the full tank can be emptied by the waste pipe alone? pls help
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Answer:
6 hours
Step-by-step explanation:
Let supply pipe be denoted by s and waste pipe be denoted by w
(s-w). s
12. 4
\. /
1 \. /. 3 (efficiencies)
12. (LCM/total work)
time by waste pipe alone = 12/(s - (s-w)) = 12/(3-1) = 6 hours
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