Question

if both the zeroes of the quadratic polynomial ax^2 + bx+c are equal and opposite in sign, then find the value of 'b'​

Answer 1

for a quadratic equation

zeroes= Y and -Y

-Y^2=-b/a

B/a=Y^2

B=aY^2

Answer 2

Answer:

b = 0

Step-by-step explanation:

Let

p and -p are two zeroes of the quadratic polynomial which are equal and opposite sign.

We know that

Sum of the zeroes = −b/a

So,

p+(−p) = −b/a

0 = −b/a

Therefore

b=0

Hence, value of

b is 0