If both the zeroes of the quadratic polynomial ax2+bx+c are equal and opposite
Answers
Answered by
1
Hola there,
Given the Equations : ax² + bx + c and the roots : [ +α , -α ]
Since the equation is Quadratic, a ≠ 0
We have : ( -b / a ) = ( +α - α ) = 0
=> b = 0
Hence, the equation is : ax² + c, with roots : ± √( -c / a )
Also, this implies that, either of 'c' or 'a' is -ve but not both, i.e., 'c' and 'a' have opposite signs
Hope this helps ...:)
Given the Equations : ax² + bx + c and the roots : [ +α , -α ]
Since the equation is Quadratic, a ≠ 0
We have : ( -b / a ) = ( +α - α ) = 0
=> b = 0
Hence, the equation is : ax² + c, with roots : ± √( -c / a )
Also, this implies that, either of 'c' or 'a' is -ve but not both, i.e., 'c' and 'a' have opposite signs
Hope this helps ...:)
Similar questions