Question

if both (x+1) and (x-1) are the factors of ax³+x²-2y+b then find a and b​

Answer 1

Answer:

Let p(x) = ax3 + x2 - 2x + b

Since (x+1) and (x-1) are the factors of p(x),

∴ p(-1) = 0 and p(1) = 0

∴ p(-1) = a(-1)3 + (-1)2 - 2 (-1) + b = 0

⇒ - a + 1 + 2 + b = 0

⇒ a - b = 3 ---- (i)

Again, p(1) = a(1)3 + (1)2 - 2(1) + b = 0

⇒ a + 1 - 2 + b = 0

⇒ a + b = 1 ----- (ii)

solving equations (i) and (ii) we get a = 2 and b = -1

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