Math, asked by Tasneetsinghajmai, 1 year ago

if both
(x-2) and (2x-1) are factors of
a {x}^{2}  + 5x + b
show that a-b=0

Answers

Answered by aman190k
1
Hey here is your answer
________________________

if both
(x-2) and (2x-1) are factors of
a {x}^{2} + 5x + b....( 1 )

then
( x-2 ) × ( 2x-1 )=2 {x}^{2} + 5x + 2...( 2 )
is also the factor of
a {x}^{2} + 5x + b

Now by comparing equation 1. and 2. we get :

a {x}^{2} + 5x + b = 2 {x}^{2} + 5x + 2

a {x}^{2} + b = 2 {x}^{2} + 2

a = 2 ( coefficient of {x}^{2} )
b = 2 ( constant term )

Now,
= a - b
= 2 - 2
= 0......proved
_________________________

Hope it may helpful to you
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Answered by Lokeshwarreddy
1
hope this helps u .thanks for asking this question.
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