Math, asked by yasminslm786, 1 month ago

if both (x-2) and (x-1/2) are factor of px^2+5+r, then p+r=0

Answers

Answered by srijansarvshresth135
1

Step-by-step explanation:

(x-2) and (x-1/2) are factors means 2,1/2 are roots so put 2 , 1/2 in equation one by one

put 2

4p + 10 + r = 0 ----->1

put 1/2

p/4 + 5/2 + r = 0 ----->2

15p/4 + 15/2 = 0

15p/4 = - 15/2

p = - 2

according to the condition given ,

p + r = 0

p = - r

r = 2

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