if both (x-2) and (x-1/2) are factors of px......
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well the method is to put x-2=0
x=2
then put x=2 in px^2+5x+r=0(zero bcoz if it's a factor then remainder will be zero as per remainder theorem)
then transport the values here and there and you will find the value of either r or p
then repeat with x-1/2
and put the obtained value of r or p from the last factor equation (x=2)
then you will get the remained value.
then if the value of r and p is equal, the problem is solved.
x=2
then put x=2 in px^2+5x+r=0(zero bcoz if it's a factor then remainder will be zero as per remainder theorem)
then transport the values here and there and you will find the value of either r or p
then repeat with x-1/2
and put the obtained value of r or p from the last factor equation (x=2)
then you will get the remained value.
then if the value of r and p is equal, the problem is solved.
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