Math, asked by kichuneeru14, 7 months ago

if both (x-2)and (x-1/2)are the factors of px2+6x+r then p+r=0​

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Answered by manthansarkar1983
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Answer:

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rajesharya119owh8k4

18.09.2017

Math

Secondary School

+5 pts

Answered

If both x-2 and x-1/2 are factors of px²+5x+r show that p=r

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siddhartharao77

siddhartharao77 Genius

Given, f(x) = px^2+5x+r and factors are x-2, x-1/2

Substitute x = 2 in place of equation, we get

= p*2^2+5*2+r=0

= 4p + 10 + r = 0 ------------ (i)

Substitute x = 1/2 in place of equation.

p/4 + 5/2 + r = 0

p + 10 + 4r = 0 ------------------- (ii)

On solving (i),(ii) we get

4p+r=-10 and p+4r+10=0

4p+r=p+4r

3p=3r

p = r.

Answered by parekhprachi14
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Answer:

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