if both (x-2)and (x-1/2)are the factors of px2+6x+r then p+r=0
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rajesharya119owh8k4
18.09.2017
Math
Secondary School
+5 pts
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If both x-2 and x-1/2 are factors of px²+5x+r show that p=r
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siddhartharao77
siddhartharao77 Genius
Given, f(x) = px^2+5x+r and factors are x-2, x-1/2
Substitute x = 2 in place of equation, we get
= p*2^2+5*2+r=0
= 4p + 10 + r = 0 ------------ (i)
Substitute x = 1/2 in place of equation.
p/4 + 5/2 + r = 0
p + 10 + 4r = 0 ------------------- (ii)
On solving (i),(ii) we get
4p+r=-10 and p+4r+10=0
4p+r=p+4r
3p=3r
p = r.
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