Question

if both x-4and x-1/4 are the factors of ax2 +5x+b, show that a=b​

Answer 1

Answer:

Since, x-4and x-1/4 are the factors of ax2 +5x+b.

ax2 +5x+b=(x-4) (x-1/4)

Or, ax2 +5x+b=x (x-1/4) -4(x-1/4)

or, ax2 +5x+b= x^2-1/4x-4x+1

comparing both sides,we get,

a=1,b=1

so, a=b

(proved)