if bulk modulus of lead is 8.0 into 10 to the power 9 Newton per metre square and initial density of lead is 11.4 gram per centimetre cube then under pressure of 2.0 into 10 to the power 8 Newton per metre square the density of lead is
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Let the initial volume of lead be V₁ and final volume V₂
Given,
Pressure (p) = 2 ×10⁸ N/m₂
Bulk modulus (B) = 8 × 10⁹ N/m²
If the change in volume is ΔV,
Then,
If the mass of lead is m and initial density is р₁ and final density is р₂
m = р₁V₁ = р₂V₂
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