Question

IF BV = BH then
VALUE OF Dip is
-​

Answer 1

Angle of dip is an acute angle given by,

$\sf{\longrightarrow\delta=\tan^{-1}\left(\dfrac{B_V}{B_H}\right)}$

where,

• $\sf{B_V=}$ vertical component of earth's magnetic field.

• $\sf{B_H=}$ horizontal component of earth's magnetic field.

Here,

$\sf{\longrightarrow B_V=B_H}$

Dividing by $\sf{B_H,}$

$\sf{\longrightarrow \dfrac{B_V}{B_H}=1}$

Taking tan inverse,

$\sf{\longrightarrow \tan^{-1}\left(\dfrac{B_V}{B_H}\right)=\tan^{-1}(1)}$

$\sf{\longrightarrow\underline{\underline{\delta=45^o}}}$

Hence 45° is the angle of dip.