Question

if bxy = 0.6, r = 0.8,variance of x = 9, variance of y ?​

Answer 1

Step-by-step explanation:

Given data

Correlation coefficient r2 between x and y=0.6

Covariance =27

.Variance of y=25

Variance ofy=25

SD =5.

Putting values

CORRELATIONCOEFFICIENT = (xy)/ SDofx ×Sd ofy

0.6= 27/SDOFX ×5

SDOFX ×5×0.6=27

Sdofx= 27÷3=9

Variance of x=sqare of Sd =9°2=81

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