Question

if bz+cY / b-C = Cx+az/ c-a=ay+bz/a-b=1 , then (a+b+c) (x+y+z)= =ax+by+cz​

Answer 1

Answer:

If the equations (b+c)x+(c+a)y+(a+b)z=0; cx+ay+bz=0; ax+by+cz=0 have non-zero solutions then a relation among a, b, c is