Question

If C(-1,0) and D(-4,2) are the points of trisection of the line segment AB what is the length of AB

Answer 1

Answer:

10.81 unit

Step-by-step explanation:

10.81 units

Answer 2

AB is approximately 10.82 units in length.

Step-by-step explanation:

We are given the following in the question:

C(-1,0) and D(-4,2)

C and d are point of trisection of AB.

Length of CD =

$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\\d = \sqrt{(-4+1)^2 + (2-0)^2}\\d = \sqrt{9+4}\\d = \sqrt{13}\text{ units}$

The length of AB is 3 times the length of CD as C and D are points of trisection of AB.

Length of AB =

$AB = 3\times \sqrt{13} = 10.82\text{ units}$

Thus, AB is approximately 10.82 units in length.

#LearnMore

The line segment AB joining the points A(2,-4) and B(5,2) is trisected at the points C(3,a) and D(b,a) .Find value of a & B??

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