If c_1/c=4,show that c^2_[1/c]=18
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given c-1/c=4
squaring on both sides
then we get
c^2+(1/c^2)-2×c×(1/c)=16
c^2+1/c^2-2=16
c^2+(1/c^2)=16+2=18
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squaring on both sides
then we get
c^2+(1/c^2)-2×c×(1/c)=16
c^2+1/c^2-2=16
c^2+(1/c^2)=16+2=18
i hope it is helpful for u
if it is useful for u plss mark it as a BRAINLIST
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