Question

If C, F and K are the temperature on Celsius, Fahrenheit and Kelvin scale, DeltaC,DeltaF and DeltaK are the change in temperature in celsium, Fahrenheit and Kelvin scale, respectively, the correct relation among the following is:-

Answer 1

hope you got your answer

this is the relation between C , K and F scales

Answer 2

$\Large{\underline{\underline{\bf{Solution :}}}}$

We know that,

$\large{\implies{\boxed{\boxed{\sf{\frac{C}{5} = \frac{K - 273}{5} = \frac{F - 32}{9}}}}}}$

Where,

C = Celsius

F = Fahrenheit

K = Kelvin

$\rule{150}{2}$

F = 68

Now, A.T.Q

$\sf{→\frac{C}{5} = \frac{68 - 32}{9}} \\ \\ \sf{→C = \frac{\cancel{36} \times 5}{\cancel{9}}} \\ \\ \sf{→C = 4 \times 5} \\ \\ \sf{→C = 20} \\ \\ \sf{So, \: 68^{\circ}F = 20^{\circ}C....(1)}$

$\rule{200}{2}$

Now,

$\sf{→\frac{K - 273}{5} = \frac{68 - 32}{9}} \\ \\ \sf{→K - 273 = \frac{\cancel{36} \times 5}{\cancel{9}}} \\ \\ \sf{→K - 273 = 4 \times 5} \\ \\ \sf{K - 273 = 20} \\ \\ \sf{→K = 20 + 273} \\ \\ \sf{K = 293} \\ \\ \sf{So, 20^{\circ}C = 293^{\circ}K ......(2)}$

★ From equation (1) and (2)

‡ 68°F = 20°C = 293°K