if c is inversely proportional to d and c=18 when d=2/3 find the value of d when c=6/7
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this is a case of inverse variation.
xy = k(constant)
18×2/3=6/7
12=6/7
12×7=6
xy = k(constant)
18×2/3=6/7
12=6/7
12×7=6
pranav2225:
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