Question

If C is right angle of a ∆ABC, then
(sin²A/sin²B)-(cos²A/cos²B) is equal to
(1)(a²-b²)/ab
(2)(a⁴-b⁴)/a²b²
(3)(a⁴+b⁴)/a²b²
(4)(a²+b²)/ab

Answer 1

Step-by-step explanation:

(a² + b²)[(a²)² - a²b² + (b²)²] … … [using algebraic formula: a³ + b³ = (a+b)(a²- ab+b²)]. = (a² + b²)[a⁴ - a²b² + b⁴]