Question

If C is the midpoint of A(0,0), B(4,8) then midpoint of CB is
a) (2, 4)
b) (3,6)
c) (1, 2)​

Answer 1

Step-by-step explanation:

mid pont of AB=then c(x,y)=( x1+x2/2. ,y1+y2/2)

c(x,y)=(0+4/2,0+8/2)=(4/2,8/2)=(2,4)

now the midpoint of c(2,4). B(4,8)

(2+4/2,4+8/2). =(6/2,12/2) =(3,6)

Answer 2

C ( x,y) = (0+4/2 , 0+8 /2)

C ( x,y) = (4/2 , 8/2)

C ( x,y) = (2 , 4)

now, let midpoint of CB as 'D'

so,

D( x,y)=(2+4/2 ,4+8/2)

D( x,y)=(6/2 ,12/2)

D( x,y)=(3,6)

so potion b is correct.....